in fig 1 determine,is ∆ ABC is right angled at B?
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Answered by
4
if <B =90
according to Pythagoras theorem
AB²+BC²= AC²
from the fig 1
AB= 2,BC=2,AC=3
2²+2²=3²
4+4=9
8=9 [false]
therefore
<B ≠90
according to Pythagoras theorem
AB²+BC²= AC²
from the fig 1
AB= 2,BC=2,AC=3
2²+2²=3²
4+4=9
8=9 [false]
therefore
<B ≠90
GAURAV1998:
sir need 1,2,3 answer any idea?
Answered by
2
Q1
Take the biggest side = AC = 3cm
check if AC² = AB² + BC²
9 = 2² + 2²
Not true. Hence Pythagoras theorem is not applicable for ΔABC. So it is not a right angled triangle.
Q2:
Angle at R is same in both triangles. (vertical angles/opposite angles). There is a right angle in each triangle. As the sum of three angles is 180 deg, the third angles are equal in both triangles.
So they are similar triangles.
Q3:
in ΔDNE: DN² = DE² + EN² = (9+4)² = 169
in ΔNEQ: EQ² = NE² - 9²
in ΔDEQ : EQ² = DE² - 4²
Add these two equations:
EQ² = [NE² + DE² - 81 - 16]/2
= (169-81-16)/2
EQ = 6
Take the biggest side = AC = 3cm
check if AC² = AB² + BC²
9 = 2² + 2²
Not true. Hence Pythagoras theorem is not applicable for ΔABC. So it is not a right angled triangle.
Q2:
Angle at R is same in both triangles. (vertical angles/opposite angles). There is a right angle in each triangle. As the sum of three angles is 180 deg, the third angles are equal in both triangles.
So they are similar triangles.
Q3:
in ΔDNE: DN² = DE² + EN² = (9+4)² = 169
in ΔNEQ: EQ² = NE² - 9²
in ΔDEQ : EQ² = DE² - 4²
Add these two equations:
EQ² = [NE² + DE² - 81 - 16]/2
= (169-81-16)/2
EQ = 6
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