Question

In Fig. 1, O is the centre of circle. PQ is a chord and PT is tangent at p which makes an angle of 50° with PQ. angle POQ is
(a) 130°
(b) 90°
(c) 100°
(d) 75°​

Answer 1

(C) 100

Angle PQO= 90-anglePQT
=90 - 50
=40
PO=QO
Angle OPQ= angle OQP =40

Angle OPQ+ angle OQP+ angle POQ=180
40+40+ anglePOQ =180
80+ anglePOQ =180
AnglePOQ=100