In Fig.10.117,PQ||AB and PR||BC If angle QPR =120°, determine angle ABC. Give reason
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Given:
PQ || AB, ∠QPR = ∠BGR =102° [Corresponding angles of parallel lines are equal] And PR || BC,
∠RGB+ ∠CBG =180° [Corresponding angles are supplementary]
∠CBG = 180° – 102° = 78°
Since, ∠CBG = ∠ABC
∠ABC = 78°
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