In Fig. 10.134, if AB = AC and ∠B = ∠C. Prove that BQ = CP.
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BQ = CP if AB = AC and ∠B = ∠C.
Step-by-step explanation:
in ΔABQ & ΔACP
∠A = ∠A ( common angle)
AB = AC given
∠B = ∠C given
=> ΔABQ ≅ ΔACP
=> BQ = CP
QED
Proved
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Answered by
4
in ΔABQ & ΔACP
∠A = ∠A ( common angle)
AB = AC given
∠B = ∠C given
=> ΔABQ ≅ ΔACP
=> BQ = CP
QED
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