Question

In Fig. 10.136, AB ⊥ BE and FE ⊥ BE. If BC=DE and AB=EF, then Δ ABD is congruent to
A. Δ EFC
B. Δ ECF
C. Δ CEF
D. Δ FEC

Answer 1

D. Δ FEC is congruent with Δ ABD

AB = FE

∠ABD = ∠FEC = 90°

BD = EC (as BC = ED and CD is common in both)

So, ΔABD ≅ ΔFEC by the SAS property.

Answer 2

Answer:

Right answer is Option-D