Question

In Fig. 10.14, AB= 8 cm, BC=6 cm, AC=3 and the angle ADC = 90°, Calculate CD.​

Answer 1

Answer: in triangle ACD  by pythagoras

AD^2 = AC^2 -CD^2

AD^2 = 3^2 -X^2

AD^2 =  9-X^2

Also in triangle ABD

by pythagoras

AD^2= AB^2 - (BC+X)^2

AD^2 = 8^2 -(6+X)^2

NOW

9-x^2= 64-36-x^2-12x

now you can find it

Step-by-step explanation:

Answer 2

Answer:

Let, CD =x cm

Then from Δ ADC,

AD

2

+CD

2

=AC

2

⇒AD

2

+x

2

=3

2

⇒AD

2

=(9−x

2

In Δ ABD ,

AB

2

=BD

2

+AD

2

⇒8

2

=(6+x)

2

+(9−x

2

⇒64=36+x

2

+12x+9−x

2

⇒12x=64−45

⇒x=

12

19

CD=

12

19

cm=1.58

3

cm