Question

In Fig. 10.14, AB = 8 cm, BC = 6 cm, AC=3 cm and
the angle ADC = 90°. Calculate CD.

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Answer 1

Answer: let D point on this fig is O then solution is given below :

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Answer 2

Answer:

Step-by-step explanation:

in triangle ACD  by pythagoras

AD^2 = AC^2 -CD^2

AD^2 = 3^2 -X^2

AD^2 =  9-X^2

Also in triangle ABD

by pythagoras

AD^2= AB^2 - (BC+X)^2

AD^2 = 8^2 -(6+X)^2

NOW

9-x^2= 64-36-x^2-12x

now you can find it