Question

In fig.10.17, AB is mirror ,PQ is the incident ray and QR is the reflected ray.if angle PQR =100 Degree ,find PQA

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Answer 1

Angle between PQR is 40 degree. Because we know angle i is equal to the angle r.

Answer 2

Step-by-step explanation:

1. NQ is a normal i.e angle NQB is 90
2. since angle of reflection is equal to angle of incident therefore angle PQN is equal to angleNQR
3. NQR+PQN=100 NQR=PQN=50
4. NQB=NQR+RQB. RQB=NQB-NQR. 90-50=40
5. similarly PQA= 40