In Fig. 10.19, AB and CD are two chords of a circleintersecting each other at point E. Prove that∠AEC =1/2 (Angle subtended by arc CXA at centre+ angle subtended by arc DYB at the centre).
pravin3103:
data insufficient
it is a exemplar question its sufficient.. try if u can otherwise thanks for help
without figure it can not be answered
bye .im signing out i need 2 study for xam.
all d best
u havent said where is x and y, so the data is insufficient
paste the diagram
Answers
Answered by
9
1/2 (angle AOC) = angle ADE ..1 (Angle at the center is double the angle at other part made by arc)
1/2 (angle BED) = angle DAE ..2 (using same property as above)
angle AEC = angle ADE + angle DAE (Exterior angle equal to the sum of opposite interior angle in Δ)
angle AEC =1/2(angle AOC + angle BED) [using 1 and 2]
angle AEC =1/2(angle subtended by arc CXA at center + angle subtented by arc DYB at the center)
Hence, proved
1/2 (angle BED) = angle DAE ..2 (using same property as above)
angle AEC = angle ADE + angle DAE (Exterior angle equal to the sum of opposite interior angle in Δ)
angle AEC =1/2(angle AOC + angle BED) [using 1 and 2]
angle AEC =1/2(angle subtended by arc CXA at center + angle subtented by arc DYB at the center)
Hence, proved
Attachments:
Answered by
9
Answer:
HOPE IT HELPS
PLS MARK IT AS BRAINLIEST
AND DO FOLLOW ME
Attachments:
Similar questions