in fig . 10.32, ab = ac and ∆1 = ∆ 2 in ∆abc. give reason to show that.
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AB=AC,∠1=∠2
In △ADC and △ADB
AB=AC (given)
∠1=∠2 (given)
AD=AD (common side)
∴ By side Angle side (S.A.S) axiom of congruence, the
two △ are congruent
∴△ABC≅△ACD
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