in fig.10.32, ab= ac and ∆1 = ∆2 in b∆abc. give reasons to show that.
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Answer:
AB=AC,∠1=∠2
In △ADC and △ADB
AB=AC (given)
∠1=∠2 (given)
AD=AD (common side)
∴ By side Angle side (S.A.S) axiom of congruence, the
two △ are congruent
∴△ABC≅△ACD
Step-by-step explanation:
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