Question

In Fig. 10.5, if AOB is a diameter of the circle
and AC = BC, then ZCAB is equal to:​

Answer 1

Step-by-step explanation:

We know that the angle at circumference subtended by the diameter of the circle is right angle.

Thus ∠ACB=90

0

In △ABC

AC=BC (given)

=>∠CAB=∠CBA

Now,

∠CAB+∠CBA+∠ACB=180 degree

=>∠CAB+∠CAB=180−90

=>∠CAB=

90/2

=>∠CAB=45 degree