Question

In Fig. 10.67, OQ:PQ=3:4 and perimeter of = 60 cm. Determine PQ, OR and OP.

Answer 1

Answer:

do same as this:-

Question:-

ΔABC is an isosceles triangle in which ∠C= 90° . If AC = 6 cm, then AB=

A. 6√2 cm

B. 6 cm

C. 2√6 cm

D. 4√2cm

Answer:-

In triangle ABC

Let tge altitude be AD on BC

AC=25cm

AB=25cm

BC=14cm

Therefore DC= 1/2*BC

=1/2*14

=7

By Pythagoras theorem,

AD^2+CD^2=AC^2

AD^2+7^2=25^2

AD^2+49=625

AD^2=625-49

AD^2=576

AD=24

Therefore altitude from A on BC is 24 cm

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Answer 2

Let x be Common Ratio

⟹OQ=3x,PQ=4x

In △POQ

(OQ)

2

+(PQ)

2

=(PO)

2

⟹PO=5x

Since perimeter =60

⟹x=5

⟹PQ=20,

QR=24,

OP=25