In Fig. 10.89, if tangents PA and PB are drawn to a circle such that ∠APS = 30° and chord AC is drawn parallel to the tangent PB, then ∠ABC =
A. 60°
B. 90°
C. 30°
D. None of these
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∠ABC = 30°
Solution :-
Given :-
∠APB = 30°
∵ Tangents PA and PB are equal
∴ ∠PBA = ∠PAB = x
x + x + 30 = 180
2x + 30 = 180
2x = 150
x = 75°
∵ AC || PB
∴ ∠ABP = ∠CAB = 75° (Alternate Interior Angles)
Also,
∠ABP = ∠ACB = 75° (Alternate Segment Theorem)
Now,
∠ACB + ∠CAB + ∠ABC = 180°
75 + 75 + ∠ABC = 180
∠ABC = 180 - 150
∴ ∠ABC = 30°
So, answer is option (c) 30°
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