In Fig. 10.98, a circle touches the side DF of AEDF at H and touches ED and EF produced at K and M respectively. If EK = 9 cm, then the perimeter of ΔEDF is
A. 18 cm
B. 13.5 cm
C. 12 cm
D. 9 cm
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Answered by
0
Answer:
first apply the formula of triangle can add all the number and divide the answer with the formula
Answered by
2
Answer:
A. 18 cm
Step-by-step explanation:
Tangents from the same external point are equal in length
Thus,
EK=EM=9 cm
DK=DH
FH=FM
Perimeter of triangle EDF= ED+DH+HF+EF
=(ED+DK)+(EF+FH)
=EK+EM
=9+9
=18 cm
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