In Fig. 11.44, ABCD is a rhombus and the
diagonals AC and BD intersect each other at O.
(a) Is OB = OD? Why?
(b) Is BC = DC? Why?
(c) Is ABOC = ADOC? Why?
(d) Is BCO = DCO? Why?
Attachments:

Answers
Answered by
0
Answer:
OB=OD because ∆ AOB and∆ AOD are congruent (AB=AD, AO is common and angle AOB = angle AOD ,= 90 degree)
BC = DC because it is rhombus property that all sides are equal
Similar questions