Question

In Fig. 11, D, E, and F are midpoints of AB, AC, and BC, respectively,
and AB = AC. Prove that ADFB = AEFC.​

Answer 1

Step-by-step explanation:

AB=AC AND D,E,F ARE MIDPOINT OF AB, AC, BC

so that AD=BD=AE=EC,-–——eq1

BF=CF—-——eq2

,DF=EF—------eq3

ADFB=AD+DF+FB,-————eq4

AEFC= AE+EF+FC—————eq5

FOR, ADFB

= AD+DF+FB———————we put eq1,eq2,eq3 in it

= AE+EF+FC---------- now from eq5

=AEFC

: ADFB=AEFC

so that

lhs=rhs

hence it is proved that ADFB=AEFC

Answer 2

Answer:

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