In Fig. 12.34, prove that triangleABC congruence triangleDCB. Is AC = DB?
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Step-by-step explanation:
Proof:
In △ABC and △DCB,
CB = CB (common)
∠ABC = ∠BCD (each 90°)
and AB = CD (given)
(i) ∴ △ ABC ≅ △DCB (S.A.S. Axiom)
(ii) Hence AC = DB (c.p.c.t.)
Hence proved.
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