In Fig. 12.44,
XZ = QZ = 5
cm, angle Y = 100°.
angle XZY = 50° and
angle PQZ = 30°.
Prove that:
(a) triangle XYZ ~= triangle QPZ
(b) XY = PQ
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in ΔXYZ
∠x= 30° [angle sum property of triangle]
Similalrly,
∠QZP=50° [ vertically opposite angle of ∠YZX]
Therefore, ∠P=100°
in ΔXYZ and ΔQPZ
∠Q = ∠X = 30° {ANGLE }
XZ = QZ [ GIVEN ] { SIDE }
∠X = ∠P = 100°
∴ ΔXYZ≅ΔQPZ [ ASA ]
⇒ By CPCT XY=PQ
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