in fig. 12.82, abc is a triangle right angled at a. semicircles are drawn on ab and ac as diameters. find the area of the shaded region
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Diameter = 6c
Radius = 3cm
Area of semicircle = pi r² / 2
= pi × 3 × 3 / 2
= 22 × 9 / 7 × 2
= 14.14 cm²
Therefore area of shaded region
= 2 × (area of one semicircle)
= 2 × 14.14
= 28.28 cm²
Therefore area of shaded region is 28.28 cm²
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