Question

in fig. 12, find angle acd , angle adc and angle dae

plz tell me it's important ​

Answer 1

Answer:

In the given figure, side BC of △ABC is produced to D

Consider the △ABC

We know that the exterior angle of a triangle is equal to the sum of its interior opposite angles

∴ ∠ACD=∠ABC+∠BAC

△ACD=45

o

+75

o

∠ACD=120

o

Hence, the measures of ∠ACD is 120

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Answer 2

Answer:

Step-by-step explanation:

Given :

In fig. 12, find angle acd , angle adc and angle dae

To find :

adc and angle dae

Solution :

Angle ACB + Angle ACD = 180° (Linear

Pair)

= 100 + ACD = 180

V90

90

4.0

= Angle ACD = 80°

Angle ADC = 180 - (ACD + CAD) [ASP of triangle]

= 180-(80+50) = 180 - 130 = 50°

Angle BAC = 40° (Using ASP triangle)

Angle DAE = 180 - (DAC + BAC)

= 180 - (50 + 40) = 180 - 90 = 90°