In fig.13.30,the radius of the given circle,with centre c,is 6 cm if the chord ab is 3 cm away from the centre,calculate its length
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Let O be the center
AB the diameter.
Now by NCERT theorem a line passing through the center bisecting any chord is perpendicular to it.
Therefore
Given=EB is 4cm
So let OE be (radius-4)or (r-4)
Now in right triangle OEC by applying pythagorus theorem you will get the answer
(R-4)2+82=R2
R2+16-8R+64=R2
R2cancelled
8R=80
R=10cm
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