In Fig. 14.111, PQRS is an isosceles trapezium. Find x and y.
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Given : PQRS is an isosceles trapezium and ∠P = 2x , ∠S = 3x , ∠Q = y
We have , PQRS an isosceles trapezium , then
PS = RQ
Since the Sum of adjacent angles are supplementary, Then
= ∠P + ∠S = 180°
= 2x + 3x = 180°
= 5x = 180°
= x = 180°/5
x = 36°
Now, PS = RQ
[PQRS is an isosceles trapezium]
∠P = ∠Q
[Angle opposite to equal sides are equal ]
= 2x = y
= 2 × 36 = y
y = 72°
Hence, the values of x is 36° and y is 72°.
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Answer:
x = 36° and y = 72°
Hope this helps you.
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