Question

in fig 14.31 o is the centre of the circle.if angle PBA=42 degree,the measure of angle pan is​

Answer 1

figure is missing..kindly upload again

Answer 2

In circle C(O, r)

AB is the diameter.

So ∠APB = 90˚ (Angle in semi–circle)

(ii) Now in △APB

∠PAB = 180˚ – (∠APB + ∠ABP)

= 180˚ – (90˚ + 42˚)

= 180˚ – 132˚ = 48˚

∠PQB = ∠PAB = 48˚ (Angles of the same segment )

Hence

∠PQB = 48˚

(iii) AQPB is a cyclic quadrilateral.

Therefore

∠APB + ∠AQB = 180˚

⇒ 90˚ + ∠AQB = 180˚

⇒ ∠AQB = 180˚ – 90˚ = 90˚

But figure is missing