In Fig. 15.105, ABCD is a rectangle with sides AB = 10 cm and AD = 5 cm. Find the area of ΔEFG.
Answers
Given :ABCD is a rectangle with sides AB = 10 cm and AD = 5 cm.
To find : Area of ΔEFG.
Proof :
Since, a triangle and a parallelogram are on the same base and between the same parallel then the angle of triangle is equal to the half of the parallelogram
∴ ΔEFG and ||gm ABCD are on the same base and between same parallels. The
ar (ΔEFG) = ½ × ar(||gm ABCD)
ar (ΔEFG) = ½ × AB × AD
[Area of parallelogram = Base × Height]
ar (ΔEFG) = ½ × 10 × 5
ar (ΔEFG) = 5 × 5
ar (ΔEFG) = 25 cm²
Hence, the ar (ΔEFG) is 25 cm².
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Answer:
Step-by-step explanation:
ar (ΔEFG) = ½ × ar(||gm ABCD)
ar (ΔEFG) = ½ × AB × AD
[Area of parallelogram = Base × Height]
ar (ΔEFG) = ½ × 10 × 5
ar (ΔEFG) = 5 × 5
ar (ΔEFG) = 25 cm²