In Fig. 15.134, O is the centre of the circle, BO is the bisector of ZABC. Show that
5
AB=AC.
B
70
O
O
А
130°
B
с
A
Fig. 15.135
Fig. 15.134
nelor intersecting at B and C. ACD is
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Sorry mate I don't know the answer because I can't understand your question
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