Question

In Fig. 15.23, ABCD is a parallelogram, CE 1 AB
and BF I AD.
(a) If AB = 18 m, AD = 12 m and CE = 10 m, find
BF
(b) If AB = 25 m, CE = 15 m, BF = 20 m, find AD.​​

Answer 1

Answer:

I don't know sorry I need point

Answer 2

Answer:

1) \large\boxed{BF=12.5\:cm}

BF=12.5cm

2) \large\boxed{AD=21\:cm}

AD=21cm

Step-by-step explanation:

1) AB = 20cm, AD = 16cm, CE = 10cm, BF = ?

⇒ Area of parallelogram = 1/2 × base × altitude

⇒ Area = 1/2 × AB × CE

⇒ Area = 1/2 × 20cm × 10cm

⇒ Area = 100{cm}^{2}cm

2

We can also write it as :-

⇒ Area of parallelogram= 1/2 × base × altitude

⇒ Area = 1/2 × AD × BF

⇒ Area = 1/2 × 16cm × BF

⇒ Area = 8BF cm

Equalize both of them :-

⇒ 8BF cm = 100{cm}^{2}cm

2

⇒ 8BF = 100cm

⇒ BF = 12.5cm

\large\boxed{BF=12.5\:cm}

BF=12.5cm

2) AB = 30cm, CE = 14cm, BF = 20cm, AD = ?

⇒ Area of parallelogram = 1/2 × base × altitude

⇒ Area = 1/2 × AB × CE

⇒ Area = 1/2 × 30cm × 14cm

⇒ Area = 210{cm}^{2}cm

2

We can also write it as :-

⇒ Area of parallelogram= 1/2 × base × altitude

⇒ Area = 1/2 × AD × BF

⇒ Area = 1/2 × AD × 20cm

⇒ Area = 10AD cm

Equalize both of them

⇒ 10AD cm = 210{cm}^{2}cm

2

⇒ 10AD = 210cm

⇒ AD = \frac{210}{10} cm

10

210

cm

⇒ AD = 21 cm

\large\boxed{AD=21\:cm}

AD=21cm

Hope it helps you❤️❤️❤️