In Fig. 15.75, OE = 20 cm. In sector OSFT, square OEFG is inscribed. Find the area of the shaded region.
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Answer:
⇒ OE=OG=GF=FE=20cm [ Sides of squares ]
⇒ In right angled △OEF,(OF)
2
=(OE)
2
+(EF)
2
⇒ (OF)
2
=(20)
2
+(20)
2
⇒ (OF)
2
=400+400
⇒ (OF)
2
=800
∴ OF=20
2
cm
∴ OF=r=20
2
cm
⇒ Area of sector OSFT=
360
o
θ
πr
2
here θ=90
o
⇒ Area of sector OSFT=
360
o
90
o
×3.14×(20
2
)
2
⇒ Area of sector OSFT=
4
3.14×800
=628cm
2
⇒ Let a=20cm
⇒ Area of square OEFG=a
2
=(20)
2
=400cm
2
⇒ Area of shaded region = Area of sector OSFT - Area of square OEFG
∴ Area of shaded region =628−400=228cm
2
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