In Fig. 15.75, PQRS is a square and T and U are respectively, the mid-points of PS and QR. Find the area of Δ OTS if PQ=8 cm
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Pqrs is a square .t and u are respectively the midpoints of PS and QR .find the area of triangle OTS. if PQ is equals to 8 cm where is the point of intersection of TU and QS
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The area of Δ OTS if PQ=8 cm is 1/2 × 4 × 4 = 8cm²-
From the diagram, it can be inferred that O is the midpoint of TU as well, if we draw the other diagonal PR.
-Therefore, OT=OU
-Length of OT = OU = 4cm
-Length of ST = 4cm
-Area of ΔOTS = 1/2 × base × height
Area = 1/2 × 4 × 4 = 8cm²
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