In fig 16.09, (ii) what is the horizontal dist of point C from point P
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Sup. PA is etended to O such that angle AOB = 90°
Therefore sin30°= OB/AB
1/root2 = OB/80
OB = 80×(1.41)
OB = CP = 112.8 KM
Therefore sin30°= OB/AB
1/root2 = OB/80
OB = 80×(1.41)
OB = CP = 112.8 KM
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