In Fig. 16.122, O is the centre of the circle. Find ∠BAC.
Answers
Answer:
yuor answer is 85°
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Given : O is the centre of the circle and from figure ∠AOB = 80° and ∠AOC = 110°.
To find : ∠BAC
Proof :
We have , ∠AOB = 80° and ∠AOC = 110°.
∴ ∠AOB + ∠AOC + ∠BOC = 360°
[Complete angle]
80° + 100° + ∠BOC = 360°
190° + ∠BOC = 360°
∠BOC = 360° –190°
∠BOC = 170°
Since, the angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle.
∴ ∠BOC = 2∠BAC
170° = 2∠BAC
∠BAC = 170°/2
∠BAC = 85°
Hence ∠BAC is 85°.
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