In Fig. 16.13, ABC is an equilateral triangle of ye
6 cm. D is a point in BC such that BD = 1 cm and
is the mid-point of BC. Calculate :
(i) AE,
(ii) tan angleADC
(iii) angleADC to the nearest degree,
(iv)angleBAD to the nearest degree.
(ICSE
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the 1srt and second part is given in the pics ... if it is correct like me
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