in fig. 16.22, BE is parallel to CD, BA = BC, <ABE = 20° and <DCG = 60°. Determine <FAC.
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Answer:
<DCG =<EBC (corresponding angles of parallel lines)
< EBC = 60 ° [ <DCG =60°]
Now,
< ABC = < EBC - <EBA
or, <ABC = 60 - 20 = 40
Now, BA = BC [ given]
Therefore, <BAC = <ACB
Now,
<ABC + <BAC + <ACB = 180
or, 40 + 2<BAC = 180
or, 2<BAC = 180 - 40 = 140
or, <BAC = 70
Finally,
<FAC = <FAB - <BAC
or, <FAC = 180 - 70 [ FB is a straight line]
or, <FAC = 110
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