Question

In Fig. 19, ΔABC is isosceles with AB = AC, D is the mid-

point of base BC.

(i) Is ΔADB ≅ ΔADC?

(ii) State the three pairs of matching parts you use to arrive at

your answer.

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Answer 1

$\Huge\bf\blue{answer:}$

$\sf{ }$

$\bf\large{{\underline{To~Prove}}:}$

$\bf{~~~~~~(i)~~ΔADB ≅ ΔADC}$

$\sf{Yes.~~ΔADB ≅ ΔADC}$

$\bf{~~~~~~Three~matching~parts:}$

$\bf 1) \: \: AB = AC \: \: \sf(given) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:~~~ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \bf 2) \: \: AD = AD \: \: \sf (common \: side) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ~~~\: \: \\ \bf 3) \: \: \angle ABD= \angle ACD \: \: \sf (Isosceles \: Triangle \: Property)$