Question

In fig.2 AB || CD and l is a transversal /_ MND = 65°. Find the value of ×.​

Answer 1

Step-by-step explanation:

From E, draw EF || AB || CD. EF || CD and CE is the transversal.

∴∠DCE+∠CEF=180o        [∵ Co-interior angles]

⇒xo+∠CEF=180o⇒∠CEF=(180−xo)

Again, EF || AB and AE is the transversal.

∠BAE+∠AEF=180o      [∵ Co-interior angles]

⇒105o+∠AEC+∠CEF=180o

⇒105o+25o+(180o−xo)=180o

⇒310−xo=180o

Hence, x=130o

Answer 2

Answer:

115 is a answer this is write