Question

In fig.2, AB||CD then find the value of x.
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

ANSWER

ANSWERFrom the figure we have, ∠EPB=180

ANSWERFrom the figure we have, ∠EPB=180 o

ANSWERFrom the figure we have, ∠EPB=180 o −(5x−20

ANSWERFrom the figure we have, ∠EPB=180 o −(5x−20 o

ANSWERFrom the figure we have, ∠EPB=180 o −(5x−20 o )......(1)[ Since ∠BPE+∠QPB=180

ANSWERFrom the figure we have, ∠EPB=180 o −(5x−20 o )......(1)[ Since ∠BPE+∠QPB=180 o

ANSWERFrom the figure we have, ∠EPB=180 o −(5x−20 o )......(1)[ Since ∠BPE+∠QPB=180 o ]

ANSWERFrom the figure we have, ∠EPB=180 o −(5x−20 o )......(1)[ Since ∠BPE+∠QPB=180 o ]Again ∠PQD=∠QPB [ Similar angles]

ANSWERFrom the figure we have, ∠EPB=180 o −(5x−20 o )......(1)[ Since ∠BPE+∠QPB=180 o ]Again ∠PQD=∠QPB [ Similar angles]or, 180

ANSWERFrom the figure we have, ∠EPB=180 o −(5x−20 o )......(1)[ Since ∠BPE+∠QPB=180 o ]Again ∠PQD=∠QPB [ Similar angles]or, 180 o

ANSWERFrom the figure we have, ∠EPB=180 o −(5x−20 o )......(1)[ Since ∠BPE+∠QPB=180 o ]Again ∠PQD=∠QPB [ Similar angles]or, 180 o −(5x−20

ANSWERFrom the figure we have, ∠EPB=180 o −(5x−20 o )......(1)[ Since ∠BPE+∠QPB=180 o ]Again ∠PQD=∠QPB [ Similar angles]or, 180 o −(5x−20 o

ANSWERFrom the figure we have, ∠EPB=180 o −(5x−20 o )......(1)[ Since ∠BPE+∠QPB=180 o ]Again ∠PQD=∠QPB [ Similar angles]or, 180 o −(5x−20 o )=2x−10