In fig.2, if ∠ABC = 70°, ∠BCA = 60°, then find ∠CDB.
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if ∠ABC = 70°, ∠BCA = 60°, then ∠CDB=50°
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Angle CDB=50°
Step-by-step explanation:
In ∆ABC,By Angle sum property
Angle ACB +AngleABC +Angle BAC=180°
60°+70°+Angle BAC=180°
Therefore,Angle BAC=50°
Hence,By therom Angle on the same segment are equal.
Angle BAC=Angle CDB=50°
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