in fig.2 o is the centre of the circle. find angle ADB
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140° since the angle formed at the centre is double that at the rest of circle furthermore ACBD is a cyclic quadrilateral
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∠O=80°
reflex∠O= 360-80 = 280
Since angle subtended by a chord at the center is double the angle subtended by it on any point on the circle,
∠D = (1/2)reflex∠O
= 280/2
= 140°
∴∠D = 140°
reflex∠O= 360-80 = 280
Since angle subtended by a chord at the center is double the angle subtended by it on any point on the circle,
∠D = (1/2)reflex∠O
= 280/2
= 140°
∴∠D = 140°
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