Question

in fig.3.29,if AB//CD,CD//EF and y:z=3:7 find x

Answer 1

Answer:

Step-by-step explanation:

In the given figure,AB∥CD,CD\parallel EFandy:z=3:7$$

Let y=3a and z=7a

∠DHI=y(vertically opposite angles)

∠DHI+∠FIH=180  

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 (Interior angles on the same side of the transversal)  

⇒y+z=180  

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⇒3a+7a=180  

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⇒10a=180  

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 or a=18  

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∴y=3×18  

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=54  

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 and z=7×18  

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=126  

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Also,x+y=180  

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⇒x+54  

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=180  

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∴x=180  

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−54  

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=126  

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Hence,x=126  

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Answer 2

Answer:

Step-by-step explanation:

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