Question

in fig 3.39 chord AB ~// chord CD
Prove that
arc AC ~// arc BD ​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given : chord AB ≃ chord CD.

Given : chord AB ≃ chord CD.⇒ length (arc AB minor) = length (arc CD minor)

Given : chord AB ≃ chord CD.⇒ length (arc AB minor) = length (arc CD minor)⇒ (arc AC) + (arc CB) = (arc CB) + (arc BD)

Given : chord AB ≃ chord CD.⇒ length (arc AB minor) = length (arc CD minor)⇒ (arc AC) + (arc CB) = (arc CB) + (arc BD)⇒ length of arc (AC) = length of arc (BD)

Given : chord AB ≃ chord CD.⇒ length (arc AB minor) = length (arc CD minor)⇒ (arc AC) + (arc CB) = (arc CB) + (arc BD)⇒ length of arc (AC) = length of arc (BD)⇒ (arc AC) ≅ (arc BD)

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