Question

in fig 3 AB=CD and BF=CE prove that AE=DF?

Answer 1

Given- AB=CD, BF=EC

To prove- AE= DF

In triangles ABE AND DCF

ANGLE B= ANGLE C= 90 DEGREE

AB=CD

BF=EC

FE=EF(Common)

By SAS Congruence , Triangle ABE is congruent to Triangle DCF.

Hence, by CPCT AE= DF

Thanks. Hope it helps

   

Answer 2

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