Question

In Fig.3, O is the centre of the circle with AOB = 85º and
∠AOC = 115°, then ∠BAC is

Answer 1

85+115 =200

360-200 = 160 so

angle BAC = 160/2 = 80°

reason (angle subtended by an Arc at the centre of the circle is double the angle subtended by it at remaining point of the circle)

Answer 2

Answer:

BOC=360−115−85=160 o

Angle subtended at the center is wice the angle subtended anywhere on the arc, so

∠BAC= 1/2∠BOC=80 o

So option C is the right answer.