In fig.4.100, AOB is a straight line
<AOC=(3x-8)°, <COD=50° and <BOD=(x+10)°
Then the value of x is
a) 32°
b) 42°
c)36°
d)52°
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Answered by
18
Answer:
the correct answer is d) 52.
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Answered by
3
Answer:
<AOC=(3x-8)°, <COD=50° and <BOD=(x+10)°
now, we know that,
<AOC+ <COD+<BOD=180°
Or, (3x-8)°+50° +(x+10)°=180°
or, 3x-8°+x+10°=180°-50°
Or, 4x=130°-2°
or, x=(128/4)=32°
so, the correct option is a) 32°.
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