In fig. 4.144, we have AB||CD||EF. If AB = 6 cm, CD = x cm, EF = 10 cm, BD = 4 cm and DE = y cm, calculate the values of x and y.
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Step-by-step explanation:
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x = 3.75 cm
y = 6.67 cm
Step-by-step explanation:
Given: AB||CD||EF
AB = 6 cm, CD = x cm, EF = 10 cm, BD = 4 cm and DE = y cm
To find: x and y
Solution:
∠CED = ∠AEB (common)
∠ECD = ∠EAB (corresponding angles)
ΔECD ~ ΔEAB (by AA similarity) --- (1)
So EC/EA = CD/AB (corresponding sides)
EC/EA = x/6 ------------(2)
In ΔACD and ΔAEF
∠CAD = ∠EAF (common)
∠ACD = ∠AEF (corresponding angles)
ΔACD ~ ΔAEF (AA similarity)
So AC/AE = CD/ EF
AC/AE = x/10 ------------(3)
Adding 2 & 3, we get:
EC/EA + AC/AE = x/6 + x/10
AE/AE = (5x + 3x)/ 30
1 = 8x/30
x = 30/8 = 3.75 cm
From (1), we know:
DC/AB = ED/BE
3.75/6 = y/(y+4)
6y = 3.75y + 15
2.25y = 15
y = 15/2.25 = 6.67 cm
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