In Fig. 4.60, check whether AD is the bisector of ∠A of ∆ABC in each of the following:
(iii) AB = 8 cm, AC = 24 cm, BD = 6 cm and BC = 24 cm
(iv) AB = 6 cm, AC = 8 cm, BD = 1.5 cm and CD = 2 cm
(v) AB = 5 cm, AC = 12 cm, BD = 2.5 cm and BC = 9 cm.
Answers
SOLUTION :
(iii) GIVEN : AB = 8 cm, AC = 24 cm, BD = 6 cm and BC = 24 cm.
First check proportional ratio between sides.
DC = BC - BD
DC = 24 - 6
DC = 18
So, AB/AC = BD/DC
8/24 = 6/18
⅓ = 1/3
Here, AB/AC = BD/CD
[If a line through one vertex of a triangle divides the opposite sides in the ratio of other two sides, then the line bisects the angle at the vertex.]
Hence, AD is the bisector of ∠ A.
(iv) GIVEN : AB = 6 cm, AC = 8 cm, BD = 1.5 cm and CD = 2 cm.
First, check proportional ratio between sides.
So, AB/AC = BD/DC
6/8 =1.5/2
¾ = 3/4
Here, AB/AC = BD/CD
[If a line through one vertex of a triangle divides the opposite sides in the ratio of other two sides, then the line bisects the angle at the vertex.]
Hence, AD is the bisector of ∠ A.
(v) GIVEN : AB = 5 cm, AC = 12 cm, BD = 2.5 cm and BC = 9 cm.
First, check proportional ratio between sides.
So, AB/ AC = 5/12
BD/CD = 2.5/9 = 5/18
Here, AB/AC ≠ BD/CD
[If a line through one vertex of a triangle divides the opposite sides in the ratio of other two sides, then the line bisects the angle at the vertex.]
Hence, AD is not the bisector of ∠ A.
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