in fig 4 ABCD is a parallelogram in which angle ADC=60° and angle ACB=70°.find the measures of angle DCB,angle CAB,angle DAC( isske answers hai 120,50,70)
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CAB=70° (alternate angles are equal)
CAB+ADC+DCA=180° (sum of the angles of a triangle is 180°)
70°+60°+DCA=180°
130° +DCA=180°
DCA=180°-130°
DCA=50°
DCA+ACB=50°+70°
DCB=120°
CAB+ADC+DCA=180° (sum of the angles of a triangle is 180°)
70°+60°+DCA=180°
130° +DCA=180°
DCA=180°-130°
DCA=50°
DCA+ACB=50°+70°
DCB=120°
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