In Fig. 4, ABCD is a square of side 14 cm. Semi-circles are drawn with each side of square as diameter Find the area 22 of the shaded region. (use )
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Answer:
84 cm²
Step-by-step explanation:
From the figure, we can conclude that:
⇒ A = B = C = D
⇒ Diameter of the semi circle = 14 cm
Find the radius:
Radius = Diameter ÷ 2
Radius = 14 ÷ 2 = 7 cm
Define the centre of the square:
Let the centre of the square be "o"
Find the area of the semicircle AOB:
Area AOB = 1/2 (πr²)
Area AOB = 1/2 ((22/7)(7)²) = 77 cm²
Find the area of the semicircle COD:
Area ODC =Area AOB
Area COD = 77 cm²
Find area of the square:
Area of the square = Length²
Area of the square = 14² = 196 cm²
Find the area B and D:
Area B + D = Area of square - Semicircle AOB - Semi Circle COD
Area B + D = 196 - 77 - 77 = 42 cm²
Find the area A + B + C + D:
Area = 2 x 42 = 84 cm²
Answer: 84 cm²
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