In fig . 5.10 ,if AC=BD, then prove that AB=CD
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Step-by-step explanation:
Given,
AC=BD ... (i)
AC=AB+BC ……(ii) (Point B lies between A and C)
BD=BC+CD … (iii) (Point C lies between B and D)
Now,
substituting (ii) and (iii) in (i), we get
⇒AB+BC=BC+CD
⇒AB+BC–BC=CD
⇒AB=CD
Hence, AB=CD.
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Answer:
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