In fig .5.37, Prove that Triangle ABCis congruent to triangle PQR.
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Answer:
AQ = CR and QC is common
So, AC = QR
PQ = CB
angle Q = angle C
So , by Side Angle Side ∆ABC =~ PQR
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Step-by-step explanation:
Given,
AQ=CR ,BC = PQ and Angle ACB=angle PQR
to prove:∆ABC=~ ∆RPQ
proof:in ∆ABC and ∆RPQ
Angle ACB=angle PQR(given)
AR-CR=AC
AR-AQ =AC (AQ=CR)
QR = AC
BC =PQ (given)
.: ∆ABC=~ ∆RPQ (SAS)
hence prooved
Bhai...........
hope it is helpful.
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