Question

in fig 5.6 ∆PQR,if ∆q=40° and ∆ R = 72°then find the
shortent and the largest
sides of the triangle
Eig. 5.6​

Answer 1

Given :

• In ΔPQR, we know ∠Q= 40° and Then, ∠R = 72

To find :

• shortent and the largest sides of the triangle

Solution :

In ΔPQR,

∠P = 180°- (72° + 40°) = 68°

PQis the largest side.

[Because Side opposite to largest angle is largest]

PR is the shortest side.

[Because side opposite to shortest angle is shortest]

Extra information :

sum of all angles of a triangles 180°

A triangle has three sides, three vertices, and three angles.

The area of a triangle is equal to half of the product of its base and height.

Answer 2

Answer:

✡ Given ✡

$\leadsto$ In ∆PQR, $\angle$Q = 40° and $\angle$R = 72°

✡ To Find ✡

$\leadsto$ What is the shortent and the largest side of the triangle.

✡ Solution ✡

✏ In ∆PQR,

• $\angle$Q = 40°
• $\angle$R = 72°

Then, we know that

$\implies$ $\angle$P = 180°- (72°+40°) = 68°

Hence, In ∆PQR,

$\mapsto$ PQ is the largest side.

$\mapsto$ PR is the shortest side.

Step-by-step explanation:

HOPE IT HELP YOU